Question

(z+4)²-(z-3)(z+3)=3(z-10) was ist die lösung 

Answer 1

(z+4)²-(z-3)(z+3)=3(z-10)

z^2+8z+16- z^2 +9=3z-30 |-z^2

8z +25= 3z-30

5z +25= -30
5z= -55
z= -11