f ( x ) = 1/2 * x^4 - x^2 -1
siehe monty
Nullstelle
1/2 * x^4 - x^2 -1 = 0 | * 2
x^4- 2x^2 - 2 = 0
x^4- 2x^2 + ( 1^2 ) = 2 + 1
substitution z = x^2
z^2 - 2 * z + 1 = 3
( z - 1 )^2 = √ 3
z -1 = ± √ 3
z (1) = +√ 3 + 1
z ( 1 ) = 1.732 + 1 = 2.732
x ( 1 ) ^2 = 2.732
x ( 1,1 ) = +1.653
x ( 1,2 ) = -1.653
z (2) = -√ 3 + 1
z ( 2 ) = -0.732
x ^2 = √-0.732
keine Lösung