Innenwinkel Berechnung eines Dreickes?

Question

Berechnen Sie die Innenwinkel des Dreiecks ABC:

A(6/-1/1)

B(4/3/-3)

C(0/5/1)

Answer 1

AB = [-2, 4, -4]
AC = [-6, 6, 0]
BC = [-4, 2, 4]

α = arccos(AB * AC / (|AB| * |AC|)) = 45 Grad
β = arccos(BA * BC / (|BA| * |BC|)) = 90 Grad
γ = arccos(AC * BC / (|AC| * |BC|)) = 45 Grad