löse die gleichung durch potenzieren

Question

gleichung : 2 log x = log( 2x-10) +1

Answer 1

Hi,

mein Vorschlag:

Vorwissen: 1 = log(10)

log(ab) = log(a)+log(b)

 

2 log x = log( 2x-10) +1

log(x^2) = log(2x-10)+log(10)

log(x^2) = log(20x-100)

x^2 = 20x-100               |-20x+100

x^2-20x+100 = 0

(x-10)^2 = 0

x = 10

 

Grüße