Quadratische Gleichung mithilfe der pq-Formel: x(12x-2)+10= 3(5-2x)

Question

iii) x(12x-2)+10= 3(5-2x) Brauche  Hilfe!

Answer 1

Hi,

12x^2-2x+10 = 15-6x  |-15+6x

12x^2+4x-5 = 0            |:12

x^2 + 1/3*x - 5/12 = 0  |pq-Formel

x₁ = -5/6

x₂ = 1/2

 

Grüße

Answer 2

X(12x-2)+10=3(5-2x) |klammer auflösen 12x^2-2x+10=15-6x |-15+6x 12x^2+4x-5=0 |:12 X^2+1/3x-5/12=0 X=-1/6±Wurzel aus 1/36+5/12 X=-1/6 ± 4/6 X=1/2 x=-5/6

Answer 3

x(12x-2)+10= 3(5-2x)

12x²-2x+10=15-6x |-15

12x²-2x-5=-6x |+6x

12x²+4x-5=0 |:12

x²+1/3x-5/12=0 |pq-Formel

x_1/2=-1/3/2±√(1/3/2)²-(-5/12)

x₁= 1/2

x₂ = -5/6