Question

Berechne die Höhe hb im Dreieck ABS mit A = (0/1/1), B=(5/4/4) und c=(-6/0/0)

Answer 1

AB = B - A = [5, 3, 3]

AC = C - A = [-6, -1, -1]

hb = |AB x AC| / |AC| = | [5, 3, 3] x [-6, -1, -1] | / | [-6, -1, -1] | = 13·√19/19 = 2.982