Aloha :)
ka(t)==const296⋅e2,55+50,32=u(t−15)⋅=ve2,55−a⋅(t−15)
ka′(t)=50,32⋅=u′1⋅=ve2,55−a⋅(t−15)+50,32=u(t−15)⋅=v′e2,55−a⋅(t−15)a¨ußere⋅(−a)innere
ka′(t)=50,32⋅e2,55−a⋅(t−15)−50,32a(t−15)⋅e2,55−a⋅(t−15)
ka′(t)=50,32⋅e2,55−a⋅(t−15)(1−a(t−15))