Hallo,
\( a) \quad-\lambda_{1} \quad+\lambda_{3}=2 \)
b) \( \quad \lambda_{1}-\lambda_{2} \quad=6 \)
c) \( \quad \lambda_{1}+3 \lambda_{2}+2 \lambda_{3}=-2 \)
\( a') \quad \lambda_{3}=2+\lambda_{1} \)
\( b') \quad \lambda_{2}=-6+\lambda_{1} \)
jetzt a' und b' in c einsetzen:
\( \begin{aligned} \lambda_{1}+3\left(-6+\lambda_{1}\right)+2\left(2+\lambda_{1}\right) &=-2 \\ \lambda_{1}-18+3 \lambda_{1}+4+2 \lambda_{1} &=-2 \\ 6 \lambda _{1}-14 &=-2 \\ 6 \lambda_{1} &=12 \\ \lambda_{1} &=2 \end{aligned} \)
λ2 = - 4
λ3 = 4
