f(x) = e^(2·x + 2)
f'(x) = 2·e^(2·x + 2)
g(x) = 2·x
g'(x) = 2
Gleiche Steigung f'(x) = g'(x)
2·e^(2·x + 2) = 2 --> x = -1
f(-1) = e^(2·(-1) + 2) = 1 → P(-1 | 1)
n(x) = -1/2·(x + 1) + 1
Skizze
Plotlux öffnen f1(x) = e^(2x+2)f2(x) = 2xP(-1|1)f3(x) = -1/2(x+1)+1