Potenzaufgaben: (2^x )^{0,2} = 8, (x^3 )^2 = 729

Question

Ergänze x

a) (2^x )^0,2 = 8

sowie

(x³ )² = 729

 

Freue mich über Hilfe!

Sophie

Answer 1

(2^x)^0.2 = 8
(2^x)^{1/5} = 2^3
2^x = 2^15
x = 15


(x^3)^2 = 729
x^6 = 3^6
x = ± 3