(z+√3)3=-1
-1 = eiπ + 2kπ
(z+√3)3=-1 | 1/3
z_(k) + √3 = ei(π/3 + 2kπ/3)
z_(k) = - √3 + ei(π/3 + 2kπ/3)
z_(1) = - √3 + eiπ/3 = 1/2-(1-i/2) √(3)
z_(2) = - √3 + ei(π/3 + 2π/3) = -√3 + eiπ = -√3 - 1
z_(3) = - √3 + ei(π/3 + 4π/3) =
- √3 + e^{i(5π/3)} = 1/2-(i√3)/2