Wie forme ich die Normalform in die Scheitelpunktform um? f(x)= 1/3x^2 + 4x - 5

Question

Haalllo? :D

Wie forme ich das in die Scheitelpunkform um?

f(x)= 1/3x² + 4x - 5

Answer 1

f(x)= 1/3x² + 4x - 5

f(x)= 1/3  (  x² + 12x - 15)

f(x)= 1/3  (  x² + 12x +36 - 36  - 15)

f(x)= 1/3  ((  x + 6)^2 - 36  - 15)

f(x)= 1/3  ((  x + 6)^2 - 51)

f(x)= 1/3  (  x + 6)^2 - 17 

Answer 2

Hi

f(x)= 1/3x² + 4x - 5    

f(x)=1/3(x²+12x-15)

f(x)=1/3(x²+12x+6²-6²-15)

f(x)=1/3((x²+12x+6²)-6²-15)

f(x)=1/3((x+6)² -6²-15)

f(x)=1/3((x+6)² -51)

f(x)=1/3((x+6)² -17