Question

 $$ 127 + x³ = ( x + 1 ) ³  $$

Answer 1

127 + x³ = ( x + 1 ) ³

127 +x³ =  x³+3 x²+3x+1  |-x³

127  =  3 x²+3x+1  |-127

0= 3 x²+3x-126  |:3

0= x² +x - 42 ->PQ-Formel

0= -1/2 ± √(1/4 +168/4)

0= -1/2 ± 13/2

x₁= 6

x₂= -7

Answer 2

127+x³=(x+1)³

127+x³=x³+3x²+3x+1

0=3x²+3x-126

0=x²+x-42

0=(x+7)*(x-6)

x=-7

x=6

Answer 3

127+x^3= x^3+3x^2+3x+1

3x^2+3x-126=0

x^2+x-42=0

pq-Formel anwenden:

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